-3(x - 3)(x + 1)(x + 1)
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3x3 -3x2 - 48x - 60 = 0 simply factor out a 3... 3(x3 - x2 - 16x - 20) = 0
2x4 - 9x3 + 13x2 - 15x + 9 = 2x4 - 6x3 - 3x3 + 9x2 + 4x2 - 12x - 3x + 9 = 2x3(x - 3) - 3x2(x - 3) + 4x(x - 3) - 3(x - 3) = (x - 3)*(2x3 - 3x2 + 4x - 3) So the quotient is (2x3 - 3x2 + 4x - 3) and the remainder is 0.
3x3 - 3x2 + 2x - 2 = 3x2(x - 1) + 2(x - 1) = (3x2 + 2)(x - 1)
Assuming all the missing operational signs are pluses, that factors to (x + 3)(3x2 + 1)
Factor 90 and find a combination that would add up to 21. 3x3x5x2. Try 3x3 plus 5x2. Nope. Try 3x5 plus 3x2. 15 + 6 = 21. Got it!