3x2(x2 - 3)
9 is a multiple of 3. (3x3=9)
(9x - 10)(x + 3)
3x3 -3x2 - 48x - 60 = 0 simply factor out a 3... 3(x3 - x2 - 16x - 20) = 0
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
9y-81=9*(y-9)
3x2(x2 - 3)
9 is a multiple of 3. (3x3=9)
(9x - 10)(x + 3)
3x3 -3x2 - 48x - 60 = 0 simply factor out a 3... 3(x3 - x2 - 16x - 20) = 0
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
3 3x1=3 3x3=9
There's a chance this was notated incorrectly. It looks like it wants to be some combination of 3x and 2. 9x2 + 12x + 4 = (3x + 2)(3x + 2) or (3x + 2)2 -9x2 - 12x - 4 = -(3x + 2)2 9x2 - 12x + 4 = (3x - 2)2 -9x2 + 12x - 4 = -(3x - 2)2
18 6 x 3 (2x3) x 3 Since 2 and 3 are prime numbers, the factor tree is complete. An alternate version of the factor tree for 18 is: 18 2 x 9 2 x (3x3)
3(x + 3)(x2 - 3x + 9)
9X2 = 3X(3X) Best I can see to factor here.
well you gotta distribute the 3s and the x's so it will be like 3X3 xXx (3 times 3) (x times x)so u should get like... 9x2