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How do you factor x2 plus 5X-6 into two binomials?
x2+5x-6 = (x+6)(x-1) when factored
Why is the FOIL method not needed when multiplying two binomials?
It is only not needed if you know of another method. If FOIL is the only way you know to multiply two binomials, then it is definitely needed.
How can you factor a polynomial in standard form completely?
You can factor a polynomial using one of these steps: 1. Factor out the greatest common monomial factor. 2. Look for a difference of two squares or a perfect square trinomial. 3. Factor polynomials in the form ax^2+bx+c into a product of binomials. 4. Factor a polynomial with 4 terms by grouping.
What is the factorization of the trinomial 14x square plus 29x-15?
If you just want the answers, the factors are: (2x+5)(7x-3)=0 and the roots/x-intercepts/zeros are: x= 3/7 and x= -2.5 If you want to see the work... ax^2 + bx + c = 0 14x^2 + 29x - 15 = 0 This is type 4 factorization... so you need to find numbers that multiply to give you the product of a and c (a*c), and add to give you b. so, a*c = (14)*(- 15) = -210, and b = 29 the numbers that would satisfy these requirements are +35, and - 6 so, here's the original equation: 14x^2 + 29x - 15 = 0 you carry down the first and third terms (a and c) and place them in the same places 14x^2 - 15 = 0 you then take the numbers you found, 35, and -6, and stick them with x's in the equation... 14x^2 +35x -6x - 15 = 0 you then factor out the largest factor of the first two terms, which is 7x 7x(2x+5) and then you repeat for the next two terms, the largest factor is -3 -3(2x+5) so here's your new equation: 7x(2x+5) -3 (2x+5) = 0 note that the two binomials are the same... take one of the binomials (2x+5)... this is one of your factors... and then the others terms (the coefficients) and put them into one binomial (7x-3) your other factor... so, your your two factors are (2x+5)(7x-3)=0 2x=-5 x= -2.5 7x=3 x=3/7 the x values are your roots/zeros/x-intercepts.
How many terms do a binomial has?
bi- = 2 Binomials have two terms.
