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How do you factor x2 plus 5X-6 into two binomials?
x2+5x-6 = (x+6)(x-1) when factored
Why is the FOIL method not needed when multiplying two binomials?
It is only not needed if you know of another method. If FOIL is the only way you know to multiply two binomials, then it is definitely needed.
How can you factor a polynomial in standard form completely?
You can factor a polynomial using one of these steps: 1. Factor out the greatest common monomial factor. 2. Look for a difference of two squares or a perfect square trinomial. 3. Factor polynomials in the form ax^2+bx+c into a product of binomials. 4. Factor a polynomial with 4 terms by grouping.
What is the factorization of the trinomial 14x square plus 29x-15?
If you just want the answers, the factors are: (2x+5)(7x-3)=0 and the roots/x-intercepts/zeros are: x= 3/7 and x= -2.5 If you want to see the work... ax^2 + bx + c = 0 14x^2 + 29x - 15 = 0 This is type 4 factorization... so you need to find numbers that multiply to give you the product of a and c (a*c), and add to give you b. so, a*c = (14)*(- 15) = -210, and b = 29 the numbers that would satisfy these requirements are +35, and - 6 so, here's the original equation: 14x^2 + 29x - 15 = 0 you carry down the first and third terms (a and c) and place them in the same places 14x^2 - 15 = 0 you then take the numbers you found, 35, and -6, and stick them with x's in the equation... 14x^2 +35x -6x - 15 = 0 you then factor out the largest factor of the first two terms, which is 7x 7x(2x+5) and then you repeat for the next two terms, the largest factor is -3 -3(2x+5) so here's your new equation: 7x(2x+5) -3 (2x+5) = 0 note that the two binomials are the same... take one of the binomials (2x+5)... this is one of your factors... and then the others terms (the coefficients) and put them into one binomial (7x-3) your other factor... so, your your two factors are (2x+5)(7x-3)=0 2x=-5 x= -2.5 7x=3 x=3/7 the x values are your roots/zeros/x-intercepts.
How many terms do a binomial has?
bi- = 2 Binomials have two terms.
How do you binomials?
There are many different methods to factor polynomials in general; specifically for binomials, you can check:whether you can separate a common factor,whether the binomial is the difference of two squares,whether the binomial is the sum or difference of two cubes (or higher odd-numbered powers)
What is a binomial factor?
Binomials are algebraic expressions of the sum or difference of two terms. Some binomials can be broken down into factors. One example of this is the "difference between two squares" where the binomial a2 - b2 can be factored into (a - b)(a + b)
Which of the binomials below is a factor if this trinomial x2 plus 6x-40?
You didn't bother to list the binomials to choose from, but the two binomial factors of x2 + 6x - 40 are (x + 10) and (x - 4)
How do you factor x2 plus 5X-6 into two binomials?
x2+5x-6 = (x+6)(x-1) when factored
How do you use algebra tiles to multiply two binomials?
Explain how I would use algebra times to multiply two binomials (FOIL)?
Which of the binomial below is a factor of this trinomial x2 plus 2x-35?
X2 + 2X - 35(X - 5)(X + 7)================take your pick of these two binomials
How do you factor the trinomial completely 18x3 29x 3x?
I'm guessing that's 18x3 + 29x2 + 3x. That factors to x(2x + 3)(9x + 1) 18x3 + 29x2 + 3x factor x = x(18x2 + 29x + 3) write 29x as 27x + 2x = x(18x2 + 27x + 2x + 3) group by two and factor each group = x[(18x2 + 27x) + (2x + 3)] = x[9x(2x + 3) + 1(2x + 3)] continue factoring = x(2x + 3)(9x + 1) Or since (18)(3) = 54 and (27)(2) = 54 then write: = x(18x2 + 29x + 3) = x[(18x + 27)/9][(18x + 2)/2] = x(2x + 3)(9x + 1)
Why is the FOIL method not needed when multiplying two binomials?
It is only not needed if you know of another method. If FOIL is the only way you know to multiply two binomials, then it is definitely needed.
What is the sum and difference pattern for the product of two binomials?
a²-b²
Which of the following are binomials?
The ones that are the sum or the difference of two terms.
You can find the product of any two binomials using what property?
distributive.
You can find the product of any two binomials using the property?
distributive
