How do you factor the trinomial completely 18x3 29x 3x?

Answer 1

I'm guessing that's 18x3 + 29x2 + 3x. That factors to x(2x + 3)(9x + 1)

18x3 + 29x2 + 3x factor x

= x(18x2 + 29x + 3) write 29x as 27x + 2x

= x(18x2 + 27x + 2x + 3) group by two and factor each group

= x[(18x2 + 27x) + (2x + 3)]

= x[9x(2x + 3) + 1(2x + 3)] continue factoring

= x(2x + 3)(9x + 1)

Or since (18)(3) = 54 and (27)(2) = 54 then write:

= x(18x2 + 29x + 3)

= x[(18x + 27)/9][(18x + 2)/2]

= x(2x + 3)(9x + 1)