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I'm guessing that's 18x3 + 29x2 + 3x. That factors to x(2x + 3)(9x + 1)
18x3 + 29x2 + 3x factor x
= x(18x2 + 29x + 3) write 29x as 27x + 2x
= x(18x2 + 27x + 2x + 3) group by two and factor each group
= x[(18x2 + 27x) + (2x + 3)]
= x[9x(2x + 3) + 1(2x + 3)] continue factoring
= x(2x + 3)(9x + 1)
Or since (18)(3) = 54 and (27)(2) = 54 then write:
= x(18x2 + 29x + 3)
= x[(18x + 27)/9][(18x + 2)/2]
= x(2x + 3)(9x + 1)
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Factor the trinomial 5x2 plus 29x-6 enter each factor as a polynomial in descending order?
(5x - 1)(x + 6)
Factor the trinomial below 14x plus 29x-15?
Assuming you mean 14x2... (7x - 3)(2x + 5)
Factor the trinomial and enter your answer below Write each factor as a polynomial in descending order14x2 plus 29x - 15?
14x2 + 29x - 15= 14x2 + 35x - 6x - 15= 7x(2x + 5) - 3(2x + 5)= (2x + 5)(7x - 3)
Factor 14x2 plus 29x - 15?
(2x+5)(7x-3)=14x2 +29x-15
Solution 5x2 plus 29x - 6?
I am assuming the question is to factor this problem? 5x2 + 29x - 6 (5x - 1)(x + 6)
Factor 15x2 29x 12?
(3x + 4)(5x + 3)
How do you factor 5X2 - 29X plus 20?
(5x - 4)(x - 5)
Factor x2 - 29x plus 100?
(x - 4)(x - 25)
How do you factor 21x2 - 29x - 10 into two binomials?
(7x + 2)(3x - 5)
What is -29x plus 3 in standard form using integers?
It is -29x + 3, exactly as in the question.
Factor as a polynomial in descending order14x2 plus 29x - 15?
(7x-3)(2x+5) 14x2 + 29x - 15, write 29x = 35x - 6x = 14x2 - 6x + 35x - 15 = (14x2 - 6x) + (35x - 15) = 2x(7x - 3) + 5(7x - 3) = (7x-3)(2x+5)
What is the simplification of 2x plus -94x-29x?
2x + -94x - 29x-121x
