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2+2y+x+xy=(x+2)(y+1)
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
if you take a factor of (Y) you end up with Y(X+5Z-2).
2+2y+x+xy
(xy - 7)(x^2y^2 + 7xy + 49)
2+2y+x+xy=(x+2)(y+1)
(x + 2)(y - 3)
xy(x - 2y)(x + 2y)
To factor the expression ( xy^2n^2 x^2y^2n ), first, identify the common factors in each term. The expression can be rewritten as ( (xy^2n^2)(x^2y^2n) ). The common factors include ( xy^2n ), which appears in both terms. Thus, the factors can be expressed as ( xy^2n (xn^2 + x^2y) ).
0
To find the greatest common factor of x^2y and xy^2, we need to determine the highest power of each variable that is common to both terms. In this case, the common factors are x and y. The highest power of x that is common to both terms is x^1, and the highest power of y that is common to both terms is y^1. Therefore, the greatest common factor of x^2y and xy^2 is xy.
(y - 3)(x + 2y)
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
if you take a factor of (Y) you end up with Y(X+5Z-2).
2+2y+x+xy
(1 - x4y4) = (1 + x2y2)*(1 - x2y2) = (1 + x2y2)*(1 + xy)*(1 - xy)
(xy - 7)(x^2y^2 + 7xy + 49)