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2+2y+x+xy=(x+2)(y+1)
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
if you take a factor of (Y) you end up with Y(X+5Z-2).
2+2y+x+xy
(xy - 7)(x^2y^2 + 7xy + 49)