2x3 + 2x2 - 24x
If we first look for something which divides into all three terms we will see that 2x does.
So we can factor to:
2x (x2 + x - 12)
However, we can also further factor the expression in the brackets. This is a quadratic expression and will factor to:
(x + 4) (x - 3)
So the original expression factors to:
2x (x + 4) (x - 3).
x(x - 19)(x - 1)
(x - 5)(x^2 + 1)
You have to put your heart into it!
x³ - x² + x - 3 (x² + 1)(x - 1) - 2
x³ + x² - 3x - 3 = (x + 1)(x + √3) (x - √3).
(a - 2)(a^2 + 6)
Factor out the GCF and get X(X2-X+1).
x(x - 19)(x - 1)
(x - 2)(x^2 + x + 3)
(x + 2)(3x - 1)(3x + 1)
(x - 5)(x^2 + 1)
(a+b)(a squared-ab+b squared)
n(2n - 1)(2n + 7)
You have to put your heart into it!
x³ - x² + x - 3 (x² + 1)(x - 1) - 2
x³ + x² - 3x - 3 = (x + 1)(x + √3) (x - √3).
x3 + 4x2 - 16x - 64 = (x + 4)(x + 4)(x - 4).