Say it looks like this: 2t+20
Do you see any common factors?
The biggest common factor in the equation would be 2, so you would divide the whole thing by 2.
2t/2 + 20/2
Then, you would solve that and come up with this.
t+10
But there is something missing :(. You need to put the 2 in front of that whole thing to show you factored it out.
(Don't forget your parenthesis to show that you are factoring the whole thing)
2(t+10)
And that's it!
Good Luck in Algebra!
3r + 3r + 2t = 6r + 2t
4t +7
(2t - 3)(7t^2 + 8)
-13
12(t+6)+8=4(2t-1)+2t 12t+72+8=8t-4+2t 12t-2t-8t=-72-8-4 2t=-84 2t/2=84/2 t=42
Rearrange as: 2t2+11t+12 = (2t+3)(t+4) when factored
(x + 2)(h + t)
(2t + 1)(3t + 11)
(t + 7)(2t - 3)
3r + 3r + 2t = 6r + 2t
4t +7
(2t - 3)(7t^2 + 8)
-13
12(t+6)+8=4(2t-1)+2t 12t+72+8=8t-4+2t 12t-2t-8t=-72-8-4 2t=-84 2t/2=84/2 t=42
If you mean t(t+7) = 4(3+2t), then it is factored. If you meant solve for 't', then the solution is t = t2 - 12.
2t
89+2t = 10t+25 89-25 = 10t-2t 64 = 8t t = 8