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Which pair of values is the solution to the system of equations below r plus 2t equals -3 and 3r-4t equals -9?
r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)
What is 2t plus 7 plus 2t?
4t +7
Suppose you're given the formula R s plus 2t. If you know that s is three times greater than t how could you rewrite the formula?
If ( s ) is three times greater than ( t ), you can express ( s ) as ( s = 3t ). Substituting ( s ) in the formula ( R s + 2t ) gives you ( R(3t) + 2t ). Simplifying this results in ( 3Rt + 2t ), which can also be factored to ( t(3R + 2) ).
Can you solve 12 parentisis t plus 6 parentissi plus 8 equals 4 parentisi 2t - 1 parentisis plus 2t?
12(t+6)+8=4(2t-1)+2t 12t+72+8=8t-4+2t 12t-2t-8t=-72-8-4 2t=-84 2t/2=84/2 t=42
How do you factor 9r squared minus 12r plus 4?
(3r - 2)(3r - 2) or (3r - 2) squared.
Which pair of values is the solution to the system of equations below r plus 2t equals -3 and 3r-4t equals -9?
r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)r + 2t = -3 . . . . (A)3r - 4t = -9 . . . . (B)2*(A) + (B): 2r + 4t + 3r - 4t = -6 - 95r = - 15 so r = -3substituting in (A), t = 0So the answer is (r, t) = (-3, 0)
What is 2t plus 7 plus 2t?
4t +7
Can r plus 2r - 3r be simplified?
5
Suppose you're given the formula R s plus 2t. If you know that s is three times greater than t how could you rewrite the formula?
If ( s ) is three times greater than ( t ), you can express ( s ) as ( s = 3t ). Substituting ( s ) in the formula ( R s + 2t ) gives you ( R(3t) + 2t ). Simplifying this results in ( 3Rt + 2t ), which can also be factored to ( t(3R + 2) ).
Can you solve 12 parentisis t plus 6 parentissi plus 8 equals 4 parentisi 2t - 1 parentisis plus 2t?
12(t+6)+8=4(2t-1)+2t 12t+72+8=8t-4+2t 12t-2t-8t=-72-8-4 2t=-84 2t/2=84/2 t=42
Is t plus t equals 2t or t squared?
2t
How do you factor 9r squared minus 12r plus 4?
(3r - 2)(3r - 2) or (3r - 2) squared.
89 plus 2t equals 10t plus 25?
89+2t = 10t+25 89-25 = 10t-2t 64 = 8t t = 8
What is 2t plus 8 equals 3t-11?
In 2t+8 19
What is 6t-2t plus 5u?
6t -2t + 5u = 4t - 5u
-7p plus 5r-6p plus 3r?
-7p + 5r - 6p + 3r = -7p - 6p + 5r + 3r = -(7 + 6)p + (5 + 3)r = -13p + 8r
What is is t plus t plus t?
It is: 2t
