The vertex has a minimum value of (-4, -11)
The vertex of the positive parabola turns at point (-2, -11)
The vertex is at the point (0, 4).
It is a parabola with its vertex at the origin and the arms going upwards.
20 and the vertex of the parabola is at (3, 20)
The minimum value of the parabola is at the point (-1/3, -4/3)
The vertex has a minimum value of (-4, -11)
It is the equation of a parabola.
The vertex of the positive parabola turns at point (-2, -11)
Question can be taken as multiple meanings. Please see discussion.
The vertex is at the point (0, 4).
The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).
It is a parabola with its vertex at the origin and the arms going upwards.
7
20 and the vertex of the parabola is at (3, 20)
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
y = x2 + 3 Since the x term is missing, the x-coordinate of the vertex is 0. If x = 0, then y = 3. Thus, (0, 3) is the vertex, the minimum point of the parabola.