3*x+6
common factor of 3&6 is 3
divide both terms by three:
3*x/3 --> x
6/3 --> 2
3(x+2)
(3x + 2)(2x + 3)
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
3x + 2 = 3x + 6 This is not possible.
(3x - 2)(2x + 6) or 2(3x - 2)(x + 3)
x2 + 3x - 18 = x2 + 6x - 3x - 18 = x(x + 6) - 3(x + 6) = (x + 6)(x - 3)
(3x + 1)(x + 6)
(3x + 2)(2x + 3)
2x2-4x-3x+6 2x2-7x+6 (2x+3)(x+2)
3x^(2) +9x - 2x -6 Collect 'like terms'. Hence 3x^(2) + 7x - 6 Next write down all the factors of '3' and '6' Hence 3 ; 1' & 3' 6 ; 1,6 ; 2,3. From these pairs of number we select a pair from each coefficient, that add/multiply to '7' . Hence (3' x 3 ) & (1' x 2) ; NB 'dashes' (') to indicate source of numbers. Write up brackets (3x 2)(x 3) -2)(x + 3) Next we notice that the '6' is negative, so the two signs are different (+/-) The '7x' is positive , so the larger number takes the positive sign . Hence (3x - 2)(x + 3)
3x3+15x2+18x = 3x(x2+5x+6) = 3x(x+2)(x+3)
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
(x + 2)(y - 3)
3x + 2 = 3x + 6 This is not possible.
(3x - 2)(2x + 6) or 2(3x - 2)(x + 3)
I know the answer is x(x^2+3x+6) + 4(x^2+3x+6) which factors to (x+4)(x^2+3x+6) but I don't know the rule behind this. Could someone explain it to me?
3X + 8You don't factor this as there are no common factors.
x2 + 3x - 18 = x2 + 6x - 3x - 18 = x(x + 6) - 3(x + 6) = (x + 6)(x - 3)