Q: How do you factor 3xsquared plus 2xy-ysquared?

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(a + 2b)(a + 2b)

Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)

The only factor is 2. 2*(t3 + 2t2 + 4x)

Two is a prime factor of that equation.

You can factor a five out of 15 plus 5x. Therefore, 15 plus 5x factors out to 5(3+x). Hope it helps :)

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The other factor is 1.

(a + 2b)(a + 2b)

Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)