Q: How do you factor 42a squared plus a minus 1?

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34

-4 + 2A = 12 - 15A + A-4 + 2A = 12 - 16A2A = 12 - 16A + 42A = 16 - 16AA = 8 - 8A

That feels like it's missing something. If that's 42a3b2, that factors to 2 x 3 x 7 x a x a x a x b x b

The LCM is 42a2b2.

Let a and b represent the numbers. ab = 185 a + b = 42 From this get b = 42 - a. Substitute into ab = 185. a(42 - a) = 185 -a2 + 42a - 185 = 0 a2 - 42a + 185 = 0 Factoring, we get (a - 5)(a - 37) = 0 Therefore the two numbers are 5 and 37.

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Are you sure it's minus 49?If so, then:9a2 +42a -49={(3a)2 + 2·3a·7 + 72} -2·72=(3a -7)2 - (7·sqrt(2))2 (2nd binomial formula)={(3a -7) + (7·sqrt(2))} · {(3a -7) - (7·sqrt(2))} (3rd binomial formula)=(3a +2,89949) · (3a -16,89949).Otherwise if it's plus 49 then simpler:9a2 +42a +49={(3a)2 + 2·3a·7 + 72}=(3a -7)2.

42 = 2 * 3 * 7 12 = 2 * 2 * 3 Hence gcf (42, 12) = 2 * 3 = 6 Notice that a is also a factor of 12a and 42a. Hence gcf (42a, 12a) = 2 * 3 * a = 6a

2 x 3 x 7 x a x a = 42a2

yes, if a=42a+3=112x4=88+3=11

34

To find the greatest common factor (GCF) of 42a^2b and 60ab^2, we first need to break down each term into its prime factors. For 42a^2b, the prime factors are 2 * 3 * 7 * a * a * b. For 60ab^2, the prime factors are 2 * 2 * 3 * 5 * a * b * b. Comparing the prime factors of both terms, we can identify the common factors: 2, 3, a, and b. Therefore, the GCF of 42a^2b and 60ab^2 is 6ab.

-4 + 2A = 12 - 15A + A-4 + 2A = 12 - 16A2A = 12 - 16A + 42A = 16 - 16AA = 8 - 8A

That feels like it's missing something. If that's 42a3b2, that factors to 2 x 3 x 7 x a x a x a x b x b

The Electric Company - 1971 42A 5-42 was released on: USA: 16 December 1975

The GCF is 6a.