The LCM is 42a2b2.
The LCM of 13 and 15 is 195. The second common multiple is 390.
The second least common multiple (LCM) of 7 and 12 is 84.
If the second number is a multiple of the prime number, than the LCM is the second number. If the second number is not a multiple of the prime number, then the two numbers are relatively prime, and the LCM is the product of the two numbers.
The answer is 16x3
Yes: product of a & b = LCM x HCF so b = (LCM x HCF)/a
36y to the second power
Since 20x7z2 is a multiple of 4x5z2, it is automatically the LCM.
36xy2
80a^3
The question is somewhat ambiguous: the answers are LCM[3T2, 5T] =15T2 or LCM[(3T)2, 5T] =45T2
LCM[(13b3)3, 7b2] = LCM[2197b9, 7b2] = 2197*7*b9 = 15379*b9
You need at least two numbers to find an LCM.
The LCM of a^2b and b^2c is a^2b^2c
The LCM of 13 and 15 is 195. The second common multiple is 390.
The second least common multiple (LCM) of 7 and 12 is 84.
11200
LCM(5y3, 25y6) = 25y6