4x2 + 34x + 42
First, we can see that each term is divisible by two, so we'll factor that out:
= 2(2x2 + 18x + 21)
To further factor the remaining trinomial, we need to find two numbers whose product is equal to the product of our first and last terms' coefficent, and whose sum is equal to the end term's coefficient. In other words, we need two numbers that add up to 18, and multiply to make 42....
Factors of 42 are 2, 3 and 7. That means that our possible combinations of numbers are: 2 and 21, 6 and 7, or 3 and 14. Unfortunately, none of these can be added up to make 18, so the polynomial can not be factored any further.
The expression cannot be factorised.
common factor is 42. so it's 35/42 + 24/42 = 59/42 = 1&17/42
(x + 7)(x - 6)
44
-x2 + x + 42 = -[x2 - x - 42] = -[x2 - 7x + 6x - 42] = -[x*(x - 7) + 6*(x - 7)] = -(x - 7)*(x + 6)
You cannot factor 4x4 + 34x + 42 The expression has a minimum value of approx 9.21616 when x = -1.286 (= 0.5*cuberoot(17). Since the expression is always positive, it does not cross the x-axis and so does not have any real roots. Consequently, it does not have any real factors.
6(x + 7)
The expression cannot be factorised.
common factor is 42. so it's 35/42 + 24/42 = 59/42 = 1&17/42
3z2 + 45z + 42 = 3(z2 + 15z + 14) = 3(z + 1)(z + 14).
It is: (x+7)(x-6) when factored
(x + 7)(x - 6)
44
NO!!! 42 is a multiple of '6'. ( 6 x 7 = 42) However, 6 is a factor of 42.
(s + 6)(6s - 7)
-x2 + x + 42 = -[x2 - x - 42] = -[x2 - 7x + 6x - 42] = -[x*(x - 7) + 6*(x - 7)] = -(x - 7)*(x + 6)
An unnecessary one. 42 + 96 = 138