(5x - 4)(x - 5)
5x2 + 20 = 5*(x2 + 4) which cannot be factorised further.
-5x2+9x-4 -5x2+9x+-4 Factors of -20 that add to equal 9 are -5 and-4 -5x2+5x+4x+-4 -5x(1x+1) + 4x(1+-1x)
5(x - 2)(x + 2)
5(x + 2)(x - 2)
(5x - 4)(x - 5)
5x2 + 20 = 5*(x2 + 4) which cannot be factorised further.
-5x2+9x-4 -5x2+9x+-4 Factors of -20 that add to equal 9 are -5 and-4 -5x2+5x+4x+-4 -5x(1x+1) + 4x(1+-1x)
5(x - 2)(x + 2)
5(x + 2)(x - 2)
i thinking this answer should be -20
20 divided by 4 multiplied by 2 plus 6 equals 16. 20/4 = 5, 5x2 = 10, 10+6 = 16.
It is 5x2 - 20
the first three are primes so we just need to factor 20 20=5x2^2 so the answer is 2^2x3x5=60
for x = -2: x2 = 4, -5x2 = -20; 3x = -6 giving -20 - (-6) = - 20 + 6 = -14.
a2+9a+20 = (a+4)(a+5) when factored
(x + 10)(x + 2)