Given a value of x, find the value for -3x + 2
5*2-3x-1 = 0 10-3x-1 = 0 -3x = 1-10 -3x = -9 x = 3
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
-5*2-3x+4 when x=-1 is -10-3*(-3)+4=-10*9+4=3
Assuming that the 2 in "5x2" is a power (5x2), then no, this is not a linear equation. It is a parabolic equation.
5
Given a value of x, find the value for -3x + 2
5*2-3x-1 = 0 10-3x-1 = 0 -3x = 1-10 -3x = -9 x = 3
explain how to evaluate an algebraic expression for given variables. how would we evaluate the expression "3x-4y+9" when x=2and y=5?
5x3 - 3x2 + 2x = x*(5x2 - 3x + 2) The quadratic has no real factors.
-5*2-3x+4 when x=-1 is -10-3*(-3)+4=-10*9+4=3
3x + 7 = 3(-3) + 7= -9 + 7= -2
5
Assuming that the 2 in "5x2" is a power (5x2), then no, this is not a linear equation. It is a parabolic equation.
7x 2= 14
(3x - 5x) + (x2 - 6x2) = -2x -5x2 = -x(2 + 5x)
if f(x) = 3x + 2 and you're looking for f(2), just plug in 2 for x: f(2) = 3(2) + 2 = 6 + 2 = 8.