the answer to factorising (a x a3 + 2ab + b2) would be (a4+2ab+b2)
(x + y)(x + y)(x + y)
2x^2y^3(4x^2 - 3xy + 1)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
105 squared plus 8 cubed is equal to 11,537.
The answer is (2x^2+3)(4x+1)
(a+b)(a squared-ab+b squared)
sin cubed + cos cubed (sin + cos)( sin squared - sin.cos + cos squared) (sin + cos)(1 + sin.cos)
(x + y)(x + y)(x + y)
2x^2y^3(4x^2 - 3xy + 1)
x(x2+5x+6)
17 squared is 289. 85 cubed is 614,125. 614,125 times 2 is 1,228,250. 1,228,250 plus 289 is 1,228,539.
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
9y cubed plus 2y squared
105 squared plus 8 cubed is equal to 11,537.
The answer is (2x^2+3)(4x+1)
Factor out the GCF and get X(X2-X+1).
4x(4x^2 + 3x + 1)