9y cubed plus 2y squared
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2y squared * y cubed= 2y^5 (2y to the fifth power)
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
7+4xz+52xz+2y=7+56xz+2y
2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+
12x-4y+9z+2y =12x-2y+9z