Factorize: a2 + 81
It doesn't look like it in its current form, but this can be changed to be a difference of two squares which can then be factorize. However to do this, we will need to use complex numbers.
a2 + 81
= a2 - (9i)2
= (a + 9i)(a - 9i)
(where i is the square root of -1)
81
x^2 + 81
92=81 402=1,600 1,600+81=1,681 I'm not super sure about this answer so don't leave bad comments!:)
Type your answer here... 81
(m + 9)(m + 9)
It is: 9^2 = 81
Three squared to the second power is 81.
4x2-36x+81 (2x-9)(2x-9)
9 to the second power :))
81. 92 = 9 * 9 = 81
(3X + 9) (X + 9)
It is 8(80b+81) when factored