(3X + 9) (X + 9)
x2-18x+81 = (x-9)(x-9) when factored
3x2 + 36x + 81 = 3(x2 + 13x + 27)
The answer to the question is: (2p+1)(2p+81) for Equation 4p^2+164p+81 P.S ^ is exponent
(m + 9)(m + 9)
(3X + 9) (X + 9)
Yes!
(p - 9)(p - 9)
x2-18x+81 = (x-9)(x-9) when factored
3x2 + 36x + 81 = 3(x2 + 13x + 27)
The answer to the question is: (2p+1)(2p+81) for Equation 4p^2+164p+81 P.S ^ is exponent
81.
If a trinomial is a perfect square, then the discriminant will equal 0. The discriminant is equal to B^2-4AC. The variables come from the standard form of a quadratic which is Ax^2+Bx+C In this problem, A=81, B=-72, and C=16 so the discriminant is: (-72)^2-4(81)(16)=5,184-5,184=0 so this is a perfect square trinomial. To factor, notice that 81=9^2 and 16=4^2, so 81x^2=(9x)^2. We can then factor the trinomial into (9x+4)(9x-4)
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (9 plus or minus 9i times the square root of 3) divided by 2y = 4.5 + 7.794228634059948iy = 4.5 - 7.794228634059948iwhere i is the square root of negative one.
Type your answer here... 81
(m + 9)(m + 9)
4x2-36x+81 (2x-9)(2x-9)