(x - 2)(x + 2)(x2 - 2x + 4)(x2 + 2x + 4)
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simplified it would equal: 24x to the third power - x to the second power - x to the sixth power - 34
One minus a sixth is five sixths.
x^7-x^6 is already in simplest form.
Twelve eighths minus one sixth is one and one third.
No, any number raised to an even power (6, in this case) is positive or zero. So, the sixth root of minus one can only be a complex number.