(t+3)3 is already factored.
Could write it as (t+3)(t+3)(t+3).
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x³ - x² + x - 3 (x² + 1)(x - 1) - 2
The answer is (2x^2+3)(4x+1)
Let x be the number. The expression is x^3+11.
x^3 + y^3 = (x + y)(x^2 - xy + y^2)
As written, this expression equals 22x + 3, which doesn't factor neatly. Make sure you copied it correctly.