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Q: How do you factor the expression t plus 3 cubed?

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Let x be the number. The expression is x^3+11.

3

As written, this expression equals 22x + 3, which doesn't factor neatly. Make sure you copied it correctly.

x^3 + y^3 = (x + y)(x^2 - xy + y^2)

2x3 + 2x2 - 24xIf we first look for something which divides into all three terms we will see that 2x does.So we can factor to:2x (x2 + x - 12)However, we can also further factor the expression in the brackets. This is a quadratic expression and will factor to:(x + 4) (x - 3)So the original expression factors to:2x (x + 4) (x - 3).

Related questions

Use a^3 + b^3 = (a + b)(a^2 - ab + b^2), where a^2 is a squared, a^3 is a cubed. Note that 216 = 6^3.

(x - 1)(x - 1)(x + 2)

It is an expression which can be written in the form of: 2x3+x+3

The only thing your going to be able to do with 2x^3+2 is factor out the common coefficient of 2. This gives you 2(x^3+1).

x³ - x² + x - 3 (x² + 1)(x - 1) - 2

The answer is (2x^2+3)(4x+1)

Let x be the number. The expression is x^3+11.

(4x - 3)(16x^2 + 12x + 9)

8(a + 3)

3

As written, this expression equals 22x + 3, which doesn't factor neatly. Make sure you copied it correctly.

x^3 + y^3 = (x + y)(x^2 - xy + y^2)

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