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How do you factor x cubed plus 3xsquaredy plus 3xy squared plus y cubed?
(x + y)(x + y)(x + y)
How do you factor 64 x cubed minus y cubed?
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
How do you factor y cubed plus 27z cubed?
(y + 27)(y^2 - 27y + 729)
What is the factor of the quantity x plus y squared?
X + Y (X + Y) ^2 = (X+Y)(X+Y) Factor = (X + Y)
Factor xz plus x plus yz plus y?
(z + 1)(y + x)
How do you factor x cubed plus 3xsquaredy plus 3xy squared plus y cubed?
(x + y)(x + y)(x + y)
How do you factor 64 x cubed minus y cubed?
64 x cubed minus y cubed is (4x - y)(16x^2 + 4xy + y^2)
How do you factor y cubed plus 27z cubed?
(y + 27)(y^2 - 27y + 729)
Can you factor the binomial below y cubed plus 27z cubed?
(y + 3z)(y^2 - 3yz + 9z^2)
What is the factor of the quantity x plus y squared?
X + Y (X + Y) ^2 = (X+Y)(X+Y) Factor = (X + Y)
Factor xz plus x plus yz plus y?
(z + 1)(y + x)
How do you factor 3xz plus 3yz plus x plus y?
3xz+3yz+x+y=(x+y)(3z+1)
What is xy cubed z squared plus y squared z plus xyz completely factorised?
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
Factor this Expression xz plus x plus yz plus y?
xz + x + yz + y = (x + y)(z + 1)
X squared plus y squared minus 1 all cubed then minus the product of x squared times y cubed that all equals 0 How do you solve for y?
You have to put your heart into it!
How do you factor y cubed plus y squared minus 6?
y^3 + y^2 - 6 (y+2) (y-3) i think
What is x minus 1 cubed?
xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1
