NOTE: xx can be written as x^2 i.e. x squared
3x^2 + 16x + 5
= 3 x^2 + x + 15x + 5 (Since 16x = x + 15x)
= x ( 3x + 1 ) + 5 ( 3x + 1 )
= ( x + 5 ) ( 3x + 1 )
Therefore the factors are ( x + 5 ) and ( 3x + 1 )
4x(4x^2 + 3x + 1)
5x2-16x+12 = (5x-6)(x-2) when factored
Too bad that's not x^2 - 16x + 64 which factors to (x - 8)(x - 8)
It is: 4x(1+4)
It is 4 terms of an algebraic expression.
The GCF is 4x.
4x(4x^2 + 3x + 1)
5x2-16x+12 = (5x-6)(x-2) when factored
Too bad that's not x^2 - 16x + 64 which factors to (x - 8)(x - 8)
(3x + 1)(x + 5)
factor the trinomial 16x^2+24x+9
True
It is: 4x(1+4)
It is 4 terms of an algebraic expression.
15x2+16x-15 = (3x+5)(5x-3) when factored
5x2 - 16x + 12 = 5x2 - 10x - 6x +12 = 5x(x - 2) - 6(x - 2) = (x - 2)(5x - 6) Whether or not these are in descending order depends on the value of x.
You don't. There is no way to factorise it.