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You can do this by finding two numbers whose sum is -9, and whose multiple is 20. Because their product is positive and their sum is negative, you know they'll both be negative numbers. So first find all of the factors of 20:
2 * 10 = 20
5 * 4 = 20
Now find which of those adds up to 9:
2 + 10 = 12
5 + 4 = 9
So we know five and four are the numbers we want. Remember though that they'll both be negative. So our end result is:
x2 - 9x + 20 = (x - 4)(x - 5)
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Can you factor 9x3 plus 15x2 plus 12x plus 20?
(3x + 5)(3x^2 + 4)
How do you factor 5X2 - 29X plus 20?
(5x - 4)(x - 5)
Factor x2 plus 9 plus 20?
x2 + 9 + 20 = x2 + 29, and can not be factored.I assume though that you mis-wrote your question, and what you in fact want to ask is how to factor x2 + 9x + 20.In that case, the answer is (x + 4)(x + 5).
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a2+9a+20 = (a+4)(a+5) when factored
Can you factor x2 plus 12x plus 20?
(x + 10)(x + 2)
If you factor out the greatest common factor of 20 x plus 45 what is the answer?
5(4x + 9)
Can you factor 9x3 plus 15x2 plus 12x plus 20?
(3x + 5)(3x^2 + 4)
Factor this Trinomial 5n2 plus 10n plus 20?
5(n2 + 2n + 4)
Factor the trinomial below Enter each factor as a polynomial in descending order.x2 plus 26x plus 120?
(x+6)(X+20)
How do you factor x2 plus x-20?
x2 + x - 20 = (x + 5)(x - 4).
Factor y2 plus y-20?
(y + 5)(y - 4)
What is the factor of 3x2 plus 7x-20?
(3x - 5)(x + 4)
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5(3a - 5b + 4)
Factor 9v2 plus 3v -20?
(3v - 4)(3v + 5)
How do you factor 5X2 - 29X plus 20?
(5x - 4)(x - 5)
