This can be done by finding two terms that add to make five, and multiply to make six. You can then use those to break the equation down further.
So first, take every combination that multiplies to make six:
1 × 6
2 × 3
-1 × -6
-2 × -3
and find the sums of each of those pairs of numbers:
1 + 6 = 7
2 + 3 = 5
-1 - 6 = -7
-2 - 3 = -5
As you can see, the only pair of numbers there that add up to five are two and three. this tells us that the factors are (x + 2) and (x + 3).
x2+5x-6 = (x+6)(x-1) when factored
You don't factor an equation. You factor an expression.So we'll forget about the "equals 0" for a second, while we factor "x2 plus 5x plus 6".x2 + 5x + 6 = (x + 3) (x + 2).Now, if you want this expression to be equal to zero, that can only happen when 'x' is -2 or -3.
x2 + 5x + 6 = (x + 2)(x + 3)
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
x2+5x+6 = (x+2)(x+3) when factored because 2 and 3 are factors of 6
x2+5x+6 = (x+2)(x+3)
x2+5x-6 = (x+6)(x-1) when factored
x(x2+5x+6)
x - 3
You don't factor an equation. You factor an expression.So we'll forget about the "equals 0" for a second, while we factor "x2 plus 5x plus 6".x2 + 5x + 6 = (x + 3) (x + 2).Now, if you want this expression to be equal to zero, that can only happen when 'x' is -2 or -3.
x2 + 5x + 6 = (x + 2)(x + 3)
x2 - 5x + 6 = (x - 2)(x - 3)
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
(x - 2)(x - 3)
(x + 11) and/or (x - 6)
which of the following is a factor of x2 - 5x - 6
3x2 + 15x + 6 = 3*(x2 + 5x + 2). There are no further rational factors.