(a+b)(a2-ab+b2) = a3+b3
So, since 27 = 33 we can reformulate to:
So, x3+33 = (x + 3)(x2-3x+32) = (x + 3)(x2-3x+9).
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125x3 + 1 ???????? 53 * x3 + 1 ================?????
a(a^2 + 1)
(x + y)(x + y)(x + y)
(y + 27)(y^2 - 27y + 729)
55