(a+b)(a2-ab+b2) = a3+b3
So, since 27 = 33 we can reformulate to:
So, x3+33 = (x + 3)(x2-3x+32) = (x + 3)(x2-3x+9).
125x3 + 1 ???????? 53 * x3 + 1 ================?????
a(a^2 + 1)
(x + y)(x + y)(x + y)
(y + 27)(y^2 - 27y + 729)
55
125x3 + 1 ???????? 53 * x3 + 1 ================?????
a(a^2 + 1)
x(x - 25)(x - 25)
(2a + c)(4a2 - 2ac + c2)
(x + y)(x + y)(x + y)
w3+125
(y + 27)(y^2 - 27y + 729)
55
sin cubed + cos cubed (sin + cos)( sin squared - sin.cos + cos squared) (sin + cos)(1 + sin.cos)
x(x^2 + 1)
x(x2 + 36)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)