3xz+3yz+x+y=(x+y)(3z+1)
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Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
(x+1)(x+8)
(x + 3)(x + 3)
(x + 3)(x + 2)
x(x4+x3+x2+x+1)