Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
(x + 3)(x + 3)
(x+1)(x+8)
(x + 3)(x + 2)
x(x4+x3+x2+x+1)
Factor x2 plus 12xp plus 36p2 is (x+6p)(x+6p).
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
It can be. x^2 + x + 1 is a factor of 2x^2 + 2x + 2
x^3 + x^2 + x = x(x^2 + x + 1)
(x + 5)(x + 8)
Oh, dude, you're hitting me with some math now? Alright, so you're looking at the quadratic expression x^2 + 5x + 4. To factor this, you want to find two numbers that multiply to 4 (the constant term) and add up to 5 (the coefficient of the x term). Those numbers are 1 and 4, so the factored form is (x + 1)(x + 4). That's it, easy peasy lemon squeezy!
(x + 2)(x + 1)
(x + 15)(x + 5)
(x + 3)(x + 3)
(x+1)(x+8)
(x + 3)(x + 2)
Factor out the GCF and get X(X2-X+1).