8(a + 3)
(j^3 + 3k^4)(j^6 - 3j^3k^4 + 9k^8)
(x + 8)(x - 3)
(4x ^2 + 3) + (3x ^2 + 8) = ( 4x^2 + 3x^2 ) + (3+8) = 7x^2 + 11
3x2 + 48 + 192 = 3x2 + 240 = 3 (x2+ 80)
8(a + 3)
(j^3 + 3k^4)(j^6 - 3j^3k^4 + 9k^8)
You must divide the entire problem by 3:3x6+24=3(x6+8)Because x6+8 is prime, 3x6+24=3(x6+8) is the final answer.
It is: 3^2 plus 2^3 = 17 meaning 9 plus 8 = 17
(11x - 8)(x + 3)
(x + 8)(x - 3)
(4x ^2 + 3) + (3x ^2 + 8) = ( 4x^2 + 3x^2 ) + (3+8) = 7x^2 + 11
3x2 + 48 + 192 = 3x2 + 240 = 3 (x2+ 80)
It is: 82-(2*8)+3 = 51
41-3 to the third power plus 8 x 2.3 - 15 is 17.4.
Is is called the exponent.
43 + 23 = 64 + 8 = 72