2x2 - 9x + 4 = (2x - 1)(x - 4)
-6 plus 2f plus 3f equals 29 -6 + 2f + 3f = 29 -6 + 5f = 29 5f = 35 f = 7
-2(-3f+6)
(a + 6)(a + 4)
p2+10d+7
3f+9 = 23 3f = 23-9 3f = 14 f = 14/3 3f+9=23 -9 -9 3f= 14 /3 /3 f= 4.66666 (6 repeats)
It is: 3(t+3)
2x2 - 9x + 4 = (2x - 1)(x - 4)
-6 plus 2f plus 3f equals 29 -6 + 2f + 3f = 29 -6 + 5f = 29 5f = 35 f = 7
-2(-3f+6)
(a + 6)(a + 4)
X=5
p2+10d+7
When you have 3f plus f plus 4f, you are adding together like terms. In this case, the variable "f" is the same, so you can add the coefficients together. 3f + f is 4f, and when you add 4f to that, you get 8f. Therefore, 3f + f + 4f equals 8f.
(x+5)(x+3)
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4c(-sq+2)