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Q: How do you factorise -4csq plus 8c?

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2a + 4b + 8c = 2(a + 2b + 4c) You could also continue by factoring the inside of the parentheses a bit: 2a + 4b + 8c = 2(a + 2b + 4c) = 2(a + 2[b + 2c])

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8c

It is: 6-11+5-8c+9c = c

-8c + 1 = -3 => -8c = -3 + 1 => -8c = -2 => c = -2/(-8) => c = 1/4 = 0.25

(a + 6)(a + 4)

It is 7 - 8c.

8c + 24 + 23 = 71subtract 47 from each side, 8c = 24divide each side by 8, c = 3

It is 7 - 8c.

X=5

p2+10d+7

-8c+1 = -3 -8c = -3-1 -8c = -4 Divide both sides by -8 in order to find the value of c remembering that a minus number divided into minus number is equal to a plus number: c = 1/2

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