Q: How do you factorize a2 plus 5a plus 6?

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Two factors of 6 that add to -5? Try -2 & -3... (x - 2)(x - 3)

(a2 + 5a + 6)/(a - 2) = (a + 2)*(a 3)/(a - 2) which cannot be simplified further. It can, however be written as (a2 - 2a + 7a - 14 + 20)/(a - 2) which is (a + 7) + 20/(a - 2)

5a2*1/6 = (5/6)a2

13a - 6 + a = 5a + 3 + 3a 13a + a - 5a - 3a = 3 + 6 6a = 9 6a/6 = 9/6 a = 3/2

6a + 2

Related questions

Two factors of 6 that add to -5? Try -2 & -3... (x - 2)(x - 3)

(a2 + 5a + 6)/(a - 2) = (a + 2)*(a 3)/(a - 2) which cannot be simplified further. It can, however be written as (a2 - 2a + 7a - 14 + 20)/(a - 2) which is (a + 7) + 20/(a - 2)

The statement is false. 5a +6 = 5a + 30 Subtract 5a from both sides: 6 = 30 and that is plain and simple rubbish!

5a2*1/6 = (5/6)a2

The value of a in the equation 5a plus 2a = 6-6a is a=6/11.

13a - 6 + a = 5a + 3 + 3a 13a + a - 5a - 3a = 3 + 6 6a = 9 6a/6 = 9/6 a = 3/2

30 + ab + 6b + 5a = 5(a+6) + b(a+6) = (b+5)(a+6)

6a + 2

It is: 2(11x+3) when factorized

8

6-3a**2+7+4a-5a+18 3a**2-1a+31

-2(x + 5)(x - 6)