The idea here is to combine terms that have the same variable (or, in more complicated cases, the same combination of variables). For example, 3a + 2a is the same as 5a.
5 x 3a= 15a
-8a + 3a = (-8 + 3)a = (5)a = 5a
9a +8 -2a -3 -5a = 2a +5
It is: 7a+1 when simplified
If 3a+5=5a+3, then: 3a+5 - 3a = 5a+3 - 3a 5=2a+3 5 - 3=2a+3 - 3 2=2a a=1
3a + 4b - 5 - 1a + 7b + 3 - 1b 2a + 10b - 5 + 3 2a + 10b - 2
(6a3 - 19a2 + 15a)/(2a - 3) = a(6a2 - 19a + 15)/(2a - 3) = a(2a - 3)(3a -5)/(2a -3) = a(3a - 5)
depends what 'a' =
2a-3+4b-2a-b-2a-b-3+5 Can be simplified to: 3b-1
2a + 4b - 52a + 4b - 52a + 4b - 52a + 4b - 5
3b -1
5a - 5 = 7 + 2a ( subtract 2a from both sides) 3a - 5 = 7 (add 5 to both sides) 3a = 12 ( divide both sides by 3) a = 4
2a+5
= 3 X 2 = 6 = a X a = a2 (a square) = 6a2 + 5 Answer
The problem 3a-1 and 2a-5 is greater by 7. This is a math problem.
The idea here is to combine terms that have the same variable (or, in more complicated cases, the same combination of variables). For example, 3a + 2a is the same as 5a.