Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter
It must be a perimeter. An area measurement would a square measurement like 56cm². ■
Even if you knew how many sides the polygon has, you stillcould not calculate its perimeter with that much information.Examples:-- An equilateral triangle with area of 20 has perimeter of 20.3885 .-- A square with area of 20 has perimeter of 17.889(rounded).-- A rectangle with area of 20 can have any perimeter more than 17.889 .4 by 5 . . . . area = 20, perimeter = 182 by 10 . . . area = 20, perimeter = 241 by 20 . . . area = 20, perimeter = 42..etc.
Because area is a function of perimeter.
zero is the least area and the max area, is of a circle of perimeter 40 .....
It is area, not perimeter!
Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter
area 63 and perimeter is 32
effectiveness of a fin is the rate of heat transfered by the fin to the rate of heat transfered without the fin.By knowing the effectiveness we can determine how a fin increases the heat transfer rate when compared to the normal surface without a fin.Whereas by determining the efficiency of a fin we can know the heat transfering capacity of the fin material. both are ratio to heat transfer by fin but, in effectiveness we take base area of fin, other hand in fin efficiency we choose fin area except base area or area which contact with surrounding.
Area : 44cm² Perimeter : 30cm
In which jobs we use perimeter and area?
It can be 56.25 or anything less, but not more. You can't tell the area from the perimeter, and you can't tell the perimeter from the area. -- if each side is 7.5, the perimeter is 30, and the area is 56.25 -- if it's (5 by 10), the perimeter is still 30, and the area is 50 -- if it's (4 by 11), the perimeter is still 30, and the area is 44 -- if it's (3 by 12), the perimeter is still 30, and the area is 36 -- if it's (2 by 13), the perimeter is still 30, and the area is 26 -- if it's (1 by 14), the perimeter is still 30, and the area is 14
It must be a perimeter. An area measurement would a square measurement like 56cm². ■
Even if you knew how many sides the polygon has, you stillcould not calculate its perimeter with that much information.Examples:-- An equilateral triangle with area of 20 has perimeter of 20.3885 .-- A square with area of 20 has perimeter of 17.889(rounded).-- A rectangle with area of 20 can have any perimeter more than 17.889 .4 by 5 . . . . area = 20, perimeter = 182 by 10 . . . area = 20, perimeter = 241 by 20 . . . area = 20, perimeter = 42..etc.
Perimeter.
There is no relationship between the perimeter and area of a rectangle. Knowing the perimeter, it's not possible to find the area. If you pick a number for the perimeter, there are an infinite number of rectangles with different areas that all have that perimeter. Knowing the area, it's not possible to find the perimeter. If you pick a number for the area, there are an infinite number of rectangles with different perimeters that all have that area.
What you have to do is to Squarerootthe Perimeter then multiply the answer by 4For example if the area is 256 , and Perimeter is ?solution=Perimeter is 64Answered by Faustin,Obedi