15X + 50 = 135 subtract 50 from both sides15X = 135-5015X = 85X = 5 and 2/3 or 17/3
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
OK, SO 15x-3 = 2x+1 15x - 3 + 3 = 2x + 1 + 3 (add three to each side) 15x=2x+4 (simplIfy) 15x-2x=2x-2x+4 (subtract 2x from each side) 13x=4 (simplify) (13x/13)=(4/13) (divide each side by 13) x≈0.30769231
6x-2=x+135x=15x=3
7x + 3 = 15x + 97x+3 = 15x+9 7x-15x = 9-3-8x = 6x = -6/8 => -3/4Explanation of working out the problem:7x+3=15x+9We want X's on one side and numbers on opposite side of Equal.When we move from one side to another, we also replace + with - and vice versa.7x-15x=9-3-8x=6We divide both sides with 2 so that we get a smallest possible answer.-4x=3I hate dealing with negative X's. it is so... negative..Multiply both sides with -1 and you get:4x=-3If you need to find X alone, then divide by 4 on both sides.x=-3/4 or in decimal terms it will be:x=-0.75And that is the end of the story :-)
X=-0.6
15X + 50 = 135 subtract 50 from both sides15X = 135-5015X = 85X = 5 and 2/3 or 17/3
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
OK, SO 15x-3 = 2x+1 15x - 3 + 3 = 2x + 1 + 3 (add three to each side) 15x=2x+4 (simplIfy) 15x-2x=2x-2x+4 (subtract 2x from each side) 13x=4 (simplify) (13x/13)=(4/13) (divide each side by 13) x≈0.30769231
Oh, dude, so like, if you want to solve for x in the equation 15x = 45, you just divide both sides by 15. So, x would equal 3. But like, who really needs math when you've got comedy, right?
-9y-15x ---- -3
The product of 15 and x is 15x. If you then want to substitute a numerical value for x to evaluate the expression of 15x when x equals that number then just multiply. For example, if x = 3, then 15x = 15(3) = 45 if x = 10, then 15x = 15(10) = 150 Good luck! :-)
3(2x - 1)(x - 2)
Do you mean? 3Y = - 15X + 6 Just divide all integers by 3 (3/3)Y = (- 15/3)X + 6/3 Y = - 5X + 2 ==============or. standard form 3Y = - 15X + 6 3Y + 15X = 6 ==============aY +bX = c
Sounds like a system of equations. Y + 5X = - 2 - 15X - 3Y = 6 substitution using first equation Y + 5X = - 2 Y = - 5X - 2 ==========insert into other equation as this is Y - 15X - 3(- 5X - 2) = 6 - 15X + 15X + 6 = 6 ========================This looks to be a dependent system that has an infinite number of solutions
6x-2=x+135x=15x=3
7x + 3 = 15x + 97x+3 = 15x+9 7x-15x = 9-3-8x = 6x = -6/8 => -3/4Explanation of working out the problem:7x+3=15x+9We want X's on one side and numbers on opposite side of Equal.When we move from one side to another, we also replace + with - and vice versa.7x-15x=9-3-8x=6We divide both sides with 2 so that we get a smallest possible answer.-4x=3I hate dealing with negative X's. it is so... negative..Multiply both sides with -1 and you get:4x=-3If you need to find X alone, then divide by 4 on both sides.x=-3/4 or in decimal terms it will be:x=-0.75And that is the end of the story :-)