First, you calculate the slope between the two points (difference of y / difference of x). Then you can use the equation, using one of the points (x1, y1):
y - y1 = m(x - x1)
Just replace x1 and y1 with the coordinates of the point, and m with with the slope.
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .
If you have two equations give AND one parametric equation why do you need to find yet another equation?
To find the equation of a line given two points with coordinates (x₁, y₁) and (x₂, y₂), first calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Then, use the point-slope form of the equation ( y - y₁ = m(x - x₁) ) to write the equation of the line. You can also rearrange this into slope-intercept form ( y = mx + b ) by solving for y and substituting the slope and one of the points to find the y-intercept (b).
To draw a flowchart for finding the equation of a circle passing through three given points, start by defining the three points as ( A(x_1, y_1) ), ( B(x_2, y_2) ), and ( C(x_3, y_3) ). Next, set up the general equation of a circle ( (x - h)^2 + (y - k)^2 = r^2 ) and derive a system of equations by substituting the coordinates of the points into this equation. Solve the resulting system of equations for the center coordinates ( (h, k) ) and the radius ( r ), and finally, express the equation of the circle in standard form.
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
The least needed information can be given in different formats, which are equivalent: -- the slope of the line and its intercept on either axis -- the slope of the line and any one point on it -- any two points on the line
Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .
If you have two equations give AND one parametric equation why do you need to find yet another equation?
I suggest that the simplest way is as follows:Assume the equation is of the form y = ax2 + bx + c.Substitute the coordinates of the three points to obtain three equations in a, b and c.Solve these three equations to find the values of a, b and c.
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
It is always easier to use an equation to find points since all you would have to do is substitute values into the equation to find the final unknown value that will tell the point. To get the equation, however, you would usually need to have some points at the start to help derive the equation in the end.
To find the equation of a line given two points with coordinates (x₁, y₁) and (x₂, y₂), first calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Then, use the point-slope form of the equation ( y - y₁ = m(x - x₁) ) to write the equation of the line. You can also rearrange this into slope-intercept form ( y = mx + b ) by solving for y and substituting the slope and one of the points to find the y-intercept (b).
The equation is -x -16 equals y. You find this by using the equation for a line mx plus b equals y, where 'm' is the slope and 'b' is the y-intercept. From the information given, you have two points which are 0.-16 ans -16,0. You can find 'm' the slope with the equation y2-y1/x2-x1, or -16-0/0- -16. This is -16/16 or -1 for m and the y-intercept is given as -16. So, substitute into the line equation these values to get the answer given.
To draw a flowchart for finding the equation of a circle passing through three given points, start by defining the three points as ( A(x_1, y_1) ), ( B(x_2, y_2) ), and ( C(x_3, y_3) ). Next, set up the general equation of a circle ( (x - h)^2 + (y - k)^2 = r^2 ) and derive a system of equations by substituting the coordinates of the points into this equation. Solve the resulting system of equations for the center coordinates ( (h, k) ) and the radius ( r ), and finally, express the equation of the circle in standard form.
No, a calculator is useless, unelss you are dealing with values for x and y which require some difficult working out. Use the general form of a linear equation using two points on the line: y - y1 = (y1 - y2)/(x1 - x2)(x - x1), where the points given are (x1, y1) and (x2, y2).