First, you calculate the slope between the two points (difference of y / difference of x). Then you can use the equation, using one of the points (x1, y1):
y - y1 = m(x - x1)
Just replace x1 and y1 with the coordinates of the point, and m with with the slope.
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .
If you have two equations give AND one parametric equation why do you need to find yet another equation?
No, a calculator is useless, unelss you are dealing with values for x and y which require some difficult working out. Use the general form of a linear equation using two points on the line: y - y1 = (y1 - y2)/(x1 - x2)(x - x1), where the points given are (x1, y1) and (x2, y2).
Subtract the equation of one line from the equation of the other
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
The least needed information can be given in different formats, which are equivalent: -- the slope of the line and its intercept on either axis -- the slope of the line and any one point on it -- any two points on the line
Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .
I suggest that the simplest way is as follows:Assume the equation is of the form y = ax2 + bx + c.Substitute the coordinates of the three points to obtain three equations in a, b and c.Solve these three equations to find the values of a, b and c.
If you have two equations give AND one parametric equation why do you need to find yet another equation?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
It is always easier to use an equation to find points since all you would have to do is substitute values into the equation to find the final unknown value that will tell the point. To get the equation, however, you would usually need to have some points at the start to help derive the equation in the end.
The equation is -x -16 equals y. You find this by using the equation for a line mx plus b equals y, where 'm' is the slope and 'b' is the y-intercept. From the information given, you have two points which are 0.-16 ans -16,0. You can find 'm' the slope with the equation y2-y1/x2-x1, or -16-0/0- -16. This is -16/16 or -1 for m and the y-intercept is given as -16. So, substitute into the line equation these values to get the answer given.
No, a calculator is useless, unelss you are dealing with values for x and y which require some difficult working out. Use the general form of a linear equation using two points on the line: y - y1 = (y1 - y2)/(x1 - x2)(x - x1), where the points given are (x1, y1) and (x2, y2).
y=mx+c where x and y are variables, m is the gradient (or slope) and c is the intercept on y (axis). that is the general equation of a straight line. if you had given some coordinates for the points one could extrapolate from that to find the full equation. since you have not, one cannot.
Subtract the equation of one line from the equation of the other