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First, you calculate the slope between the two points (difference of y / difference of x). Then you can use the equation, using one of the points (x1, y1):
y - y1 = m(x - x1)
Just replace x1 and y1 with the coordinates of the point, and m with with the slope.
What else can I help you with?
How do you find slope if the points aren't given?
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
How do you know if a quadratic equation will have one two or no solutions How do you find a quadratic equation if you are only given the solution Is it possible to have different quadratic equation?
Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .
When two planes equation given and one parametric equation is given how can you find the plane equation?
If you have two equations give AND one parametric equation why do you need to find yet another equation?
How can find the equation of a line when given the x y coordinates?
To find the equation of a line given two points with coordinates (x₁, y₁) and (x₂, y₂), first calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Then, use the point-slope form of the equation ( y - y₁ = m(x - x₁) ) to write the equation of the line. You can also rearrange this into slope-intercept form ( y = mx + b ) by solving for y and substituting the slope and one of the points to find the y-intercept (b).
How do you draw a flow chart to find the equation of a circle passing through three given points?
To draw a flowchart for finding the equation of a circle passing through three given points, start by defining the three points as ( A(x_1, y_1) ), ( B(x_2, y_2) ), and ( C(x_3, y_3) ). Next, set up the general equation of a circle ( (x - h)^2 + (y - k)^2 = r^2 ) and derive a system of equations by substituting the coordinates of the points into this equation. Solve the resulting system of equations for the center coordinates ( (h, k) ) and the radius ( r ), and finally, express the equation of the circle in standard form.
How do you find slope if the points aren't given?
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
How do you find Slope intercept equation of given two points?
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
What is the least needed information to find the equation of a line?
The least needed information can be given in different formats, which are equivalent: -- the slope of the line and its intercept on either axis -- the slope of the line and any one point on it -- any two points on the line
How do you know if a quadratic equation will have one two or no solutions How do you find a quadratic equation if you are only given the solution Is it possible to have different quadratic equation?
Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .
When two planes equation given and one parametric equation is given how can you find the plane equation?
If you have two equations give AND one parametric equation why do you need to find yet another equation?
How do you find the equation of a parabola in standard form given 3 points?
I suggest that the simplest way is as follows:Assume the equation is of the form y = ax2 + bx + c.Substitute the coordinates of the three points to obtain three equations in a, b and c.Solve these three equations to find the values of a, b and c.
How do you find the equation of a tangent line?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
Is it easier to solve an equation for y first before finding points?
It is always easier to use an equation to find points since all you would have to do is substitute values into the equation to find the final unknown value that will tell the point. To get the equation, however, you would usually need to have some points at the start to help derive the equation in the end.
How can find the equation of a line when given the x y coordinates?
To find the equation of a line given two points with coordinates (x₁, y₁) and (x₂, y₂), first calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Then, use the point-slope form of the equation ( y - y₁ = m(x - x₁) ) to write the equation of the line. You can also rearrange this into slope-intercept form ( y = mx + b ) by solving for y and substituting the slope and one of the points to find the y-intercept (b).
Find the equation of line whose intercepts are-16 for x and y respectively?
The equation is -x -16 equals y. You find this by using the equation for a line mx plus b equals y, where 'm' is the slope and 'b' is the y-intercept. From the information given, you have two points which are 0.-16 ans -16,0. You can find 'm' the slope with the equation y2-y1/x2-x1, or -16-0/0- -16. This is -16/16 or -1 for m and the y-intercept is given as -16. So, substitute into the line equation these values to get the answer given.
How do you draw a flow chart to find the equation of a circle passing through three given points?
To draw a flowchart for finding the equation of a circle passing through three given points, start by defining the three points as ( A(x_1, y_1) ), ( B(x_2, y_2) ), and ( C(x_3, y_3) ). Next, set up the general equation of a circle ( (x - h)^2 + (y - k)^2 = r^2 ) and derive a system of equations by substituting the coordinates of the points into this equation. Solve the resulting system of equations for the center coordinates ( (h, k) ) and the radius ( r ), and finally, express the equation of the circle in standard form.
How do you write the equation of a line that passes through two points given an example is it possible to find this on a calculator?
No, a calculator is useless, unelss you are dealing with values for x and y which require some difficult working out. Use the general form of a linear equation using two points on the line: y - y1 = (y1 - y2)/(x1 - x2)(x - x1), where the points given are (x1, y1) and (x2, y2).
