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How do you find the width of a rectangle when the length and perimeter is given?
You multiply the length by 2 (because there are two sides of the rectangle that have that measure). You then subtract that number from the perimeter. The number you will be left with is twice the width, so you divide that by two and you get the width of the rectangle.
How do you find the optimal area of a rectangle given its perimeter?
Multiply length by width
How do you find the perimeter of a rectangle when only the area is given?
You cannot find the perimeter unless the rectangle is a regular rectangle (a square) in which case the perimeter is 4 times the square root of the area. With just the area the shape of the rectangle could be any number of shapes with different perimeter, for example, imagine 6 square units 1cm by 1cm arranged in a 1*6 configuration to give a long thin rectangle, the perimeter would be 6+6+1+1=14cm, the same 6 arranged in a 3*2 rectangle would have the same area, but a perimeter of 3+3+2+2=10cm, for this reason a rectangle's perimeter cannot be determined from the area alone.
How do you find the length and width of rectangle when given the perimeter but not the width or length?
by appying 2l+2w
How can you find the area of a rectangle if the given is the perimeter and the diagonal?
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
