Select two distinct values of X, designated X1 and X2, from the table, read the corresponding values Y1 and Y2 from the table, and calculate the slope from the formula:
slope = (Y2 - Y1)/(X2 - X1)
Form a right angle triangle under the slope and divide the base of the triangle into the height of the triangle.
To find the xy-trace, set z = 0 in the equation -5x - 2y - 3z = 10. Simplifying, we get -5x - 2y = 10. This is the equation of the xy-trace for the given plane.
y' is a derivative so y'=xy^3 represents the slope of y. We find that the limit of y' as x approaches zero is zero. Therefore we can say that the instantaneous slope of y as x approaches zero is zero.
The greatest possible slope is 1.
Not enough information is given to class it as a straight line equation inasmuch as there is no equality sign and the plus or minus values are missing.
Form a right angle triangle under the slope and divide the base of the triangle into the height of the triangle.
True.
If the curve is on the xy-plane, finding an expression for dy/dx will give you the slope of a curve at a point.
Points for example: (4, 8) and (2, 4) Slope: (8-4)/(4-2) = 2 The slope formula is m = (y2 - y1) / (x2 - x1) where the 2 points are (x1,y1) and (x2,y2)
You're familiar with the xy-plane. A line with negative slope is one that goes down toward the right. A curve has a negative slope at a point if the tangent line to the curve at that point has a negative slope.
To find the xy-trace, set z = 0 in the equation -5x - 2y - 3z = 10. Simplifying, we get -5x - 2y = 10. This is the equation of the xy-trace for the given plane.
x = 4 is a straight line that is vertical when plotted on the xy graph, where y is the vertical axis and x is the horizontal axis. A vertical line has an infinite slope; the slope is infinity
The coefficient of xy is the number that multiplies the product of x and y in a given expression. For example, in the expression 5xy, the coefficient of xy is 5.
y' is a derivative so y'=xy^3 represents the slope of y. We find that the limit of y' as x approaches zero is zero. Therefore we can say that the instantaneous slope of y as x approaches zero is zero.
The greatest possible slope is 1.
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
Not enough information is given to class it as a straight line equation inasmuch as there is no equality sign and the plus or minus values are missing.