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Area of a square = side length squared (x+y)2 (x+y)(x+y) x2+xy+yx+y2 Area = x2+2xy+y2
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
Equations of circles are usually in x2+y2=(radius)2 form, so if you have x2 + y2 = 25 x2 + y2 = 52 then radius = 5.
y2 + x = 7 : this can be written as y2 = 7 - x or x = 7 - y2. There is not a specific solution to this identity. For each different value assigned to x then a different value is generated for y. Or, it can be viewed that for each different value assigned to y then a different value is generated for x. This expression is therefore a function.
Your expression is this... x2 + y2/x