Area of a square = side length squared (x+y)2 (x+y)(x+y) x2+xy+yx+y2 Area = x2+2xy+y2
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
Equations of circles are usually in x2+y2=(radius)2 form, so if you have x2 + y2 = 25 x2 + y2 = 52 then radius = 5.
y2 + x = 7 : this can be written as y2 = 7 - x or x = 7 - y2. There is not a specific solution to this identity. For each different value assigned to x then a different value is generated for y. Or, it can be viewed that for each different value assigned to y then a different value is generated for x. This expression is therefore a function.
Your expression is this... x2 + y2/x
x=y+3t Original formula: y2 -xy = 9t2 -3xt (assumes you meant "9 times t2 " and not (9t)2 ) y2 = xy +9t2 -3xt y2 - 9t2 = xy - 3xt (y-3t)(y+3t) = x(y-3t) (y-3t) = x
(x - y)(x + y)(x2 - xy + y2)(x2 + xy + y2)
2(x - y)(x + y)(x2 - xy + y2)(x2 + xy + y2)
Oh, dude, y squared plus y squared equals 2y squared. It's like adding two of the same things together, you know? So, if you have y squared and add another y squared, you end up with 2y squared. Math can be pretty chill sometimes, huh?
Area of a square = side length squared (x+y)2 (x+y)(x+y) x2+xy+yx+y2 Area = x2+2xy+y2
x2+y2
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
4x-y2=2xy 2x ? y5 if its plus its 7 xy
Some signs would have helped answerers but for what its worth 7 & 8 are factors of 56 which differ by 1 so how about: (y - 7x)(y + 8x) which are the factors of y2 + xy - 56x2 or (y + 7x)(y - 8x) which are the factors of y2 - xy - 56x2.
x2 + y2 = (x + y)2 => x2 + y2 = x2 + 2xy + y2 => 2xy = 0 => xy = 0 So, one of x and y must be 0.
sqrt(36) * y2 = 6*y2
If you are refering to y squared and 6y then no there is no way to combine them without knowing the value of y first