The "solution" depends on what the question is.
If you mean the roots, and if the equation of the parabola isy = ax^2 + bx + c then the roots are
[-b +/- sqrt(b^2-4ac)]/(2a)
A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.
No you can't. There is no unique solution for 'x' and 'y'. The equation describes a parabola, and every point on the parabola satisfies the equation.
To graph a parabola you must find the axis of symmetry, determine the focal distance and write the focal as a point, and find the directrix. These are all the main points you need to be able to draw a parabola.
If you can mash the equation for the parabola into the form Y = Ax2 + Bx + C, then the parabola opens up if 'A' is positive, and down if 'A' is negative.
Above
A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.
You need more than one tangent to find the equation of a parabola.
No you can't. There is no unique solution for 'x' and 'y'. The equation describes a parabola, and every point on the parabola satisfies the equation.
To graph a parabola you must find the axis of symmetry, determine the focal distance and write the focal as a point, and find the directrix. These are all the main points you need to be able to draw a parabola.
If you can mash the equation for the parabola into the form Y = Ax2 + Bx + C, then the parabola opens up if 'A' is positive, and down if 'A' is negative.
right
Above
(-1.5,0) (1.5,0) what is the gradient?
Select a set of x values and find the value of y or f(x) - depending on how the parabola is defined. These are the values that you need to graph.
The graph of the solution set of a quadratic inequality typically represents a region in the coordinate plane, where the boundary is formed by the parabola defined by the corresponding quadratic equation. Depending on the inequality (e.g., (y < ax^2 + bx + c) or (y > ax^2 + bx + c)), the solution set will include points either above or below the parabola. The parabola itself may be included in the solution set if the inequality is non-strict (e.g., ( \leq ) or ( \geq )). The regions of the graph where the inequality holds true are shaded or highlighted to indicate the solution set.
One way would be to graph the two equations: the parabola y = x² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)