y2-y1
___
x2-x1
first find any two points on a line
then take the second point's (y) and subtract it from the first points (y)
then divide by the second (x) subtracted by the first points (x) like the (y)
the first (x,y) is the left dot of your two dots and the second (x,y) is the right dot of the two
the result is the slope of the line of the graph
ex. (8,7) (13,11)
(11-7) / (13-8)
slope = 4 / 5
(4up and 5 over)
hope this helped :)
To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.
Your x and y intercepts give you two points on the line of the graph. Use these two points in the slope equation m = (y2-y1)/(x2-x1), and that gives you the slope.
6
A graph is more informative than an equation because a graph is easier to interpret visually, and find all the points and line them up, rather than just a slope which shows no points(data).
15
To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.
Your x and y intercepts give you two points on the line of the graph. Use these two points in the slope equation m = (y2-y1)/(x2-x1), and that gives you the slope.
You find the equation of a graph by finding an equation with a graph.
6
find the derivative to get the slope, then using the graph of the other line given to you, find a point on the graph that they share and plug it in to find the y-value. then use the point slope formulahttp://docs.google.com/gview?a=v&q=cache:P72siWJTFjwJ:gato-docs.its.txstate.edu/slac/Subject/Math/Calculus/Findting-the-Equation-of-a-Tangent-Line/Finding%2520the%2520Equation%2520of%2520a%2520Tangent%2520Line.pdf+how+to+find+the+equation+of+a+tangent+line&hl=en&gl=us&sig=AFQjCNFcYzt1d-PU9hE2gbQKngp4FeRw3Q
To graph the equation y-x=3, first rearrange it in slope-intercept form by isolating y: y=x+3. This equation represents a line with a slope of 1 and y-intercept of 3. You can plot the y-intercept at (0,3) then use the slope to find another point and draw a straight line connecting the two points.
A graph is more informative than an equation because a graph is easier to interpret visually, and find all the points and line them up, rather than just a slope which shows no points(data).
15
from a table to a graph just graph x and y (on a coordinate plane) from table to equation find the slope of the line and the y intercept. your equation should be in the form y=mx+b where m is the slope and b is the y intercept
A vertical line on a graph has infinite slope and no y-intercept. Its equation is [ x = a number ]. The number is the line's x-intercept.
The slope of the line (on a linear equation) is rise over run. Meaning how far apart vertically (up and down) two points on the graph are, divided by how many units apart they are horizontally (left to right).
To find instantaneous velocity from a position-time graph, you calculate the slope of the tangent line at a specific point on the graph. The slope represents the rate of change of position at that instant, which is equivalent to the velocity at that particular moment.