You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer.
Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
To find instantaneous velocity from a position-time graph, you calculate the slope of the tangent line at a specific point on the graph. The slope represents the rate of change of position at that instant, which is equivalent to the velocity at that particular moment.
To go from a position graph to a velocity graph, you can calculate the slope of the position graph at each point. The slope at any given point on a position vs. time graph represents the velocity at that specific time. Therefore, the velocity graph would be a plot of the slopes at each point on the position graph.
this time is basically the instant when an object has a particular velocity(instantaneous velocity). so on the graph draw a line from the particular value of the velocity and then draw a vertical line on time axis to find the time for that velocity.
You can calculate the velocity of a moving object from two points on a position-time graph by finding the slope of the line connecting those two points. The slope represents the average velocity of the object between those two points. Divide the change in position by the change in time to find the velocity.
Acceleration can be determined from a position vs. time graph by finding the slope of the velocity vs. time graph. The slope of the velocity vs. time graph represents the rate at which velocity is changing, which is acceleration. A steeper positive slope indicates a higher acceleration, while a steeper negative slope indicates deceleration.
To create an acceleration-time graph from a velocity-time graph, you need to find the slope of the velocity-time graph at each point. The slope represents the acceleration at that specific instant. Plot these acceleration values against time to get the acceleration-time graph.
It is the gradient (slope) of the line.
To find the position from a velocity-vs-time graph, you need to calculate the area under the velocity curve. If the velocity is constant, the position can be found by multiplying the velocity by the time. If the velocity is changing, you need to calculate the area under the curve using calculus to determine the position.
With great difficulty since the question does not specify what aspect of the object's instantaneous. Speed, position, acceleration?
A distance-time graph allows you to find information such as the speed of an object (slope of the graph), the distance traveled by the object over a specific time period, and whether the object is moving at a constant speed or accelerating. It provides a visual representation of how the position of an object changes over time.
To go from a position graph to a velocity graph, you can calculate the slope of the position graph at each point. The slope at any given point on a position vs. time graph represents the velocity at that specific time. Therefore, the velocity graph would be a plot of the slopes at each point on the position graph.
this time is basically the instant when an object has a particular velocity(instantaneous velocity). so on the graph draw a line from the particular value of the velocity and then draw a vertical line on time axis to find the time for that velocity.
Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.
To obtain average velocity from a displacement-time graph, divide the total displacement by the total time taken. For instantaneous velocity, find the slope of the tangent to the curve at a specific point on the graph. This tangent represents the velocity at that instant.
The instantaneous velocity of a body represents its velocity at a particular instant in time, while the average velocity is calculated over a certain time interval. To find the instantaneous velocity from the average velocity, you can take the limit as the time interval approaches zero in the average velocity calculation. Mathematically, this can be represented as the derivative of the position function with respect to time.
To obtain the average velocity from a displacement-time graph, you can calculate the slope of the line connecting the initial and final points on the graph. Instantaneous velocity at a specific point can be found by determining the slope of the tangent line to the curve at that point.
You cannot because a dispacement-time graph is concerned only with motion in a radial direction; any motion in a transverse direction is completely ignored. For example, an object circling the origin at a fixed distance, even with a variable speed, is always at the same distance from the origin. So the displacement-time graph will be a straight line whose height is the radial distance. A straight line in the distance-time graph is to be interpreted as no motion! Really?!The average velocity in the radial direction is the final displacement minus the starting [initial] displacement, all divided by the difference in time between the two points. The instantaneous velocity in the radial direction is the slope [gradient] of the graph at the point in question.
You can calculate the velocity of a moving object from two points on a position-time graph by finding the slope of the line connecting those two points. The slope represents the average velocity of the object between those two points. Divide the change in position by the change in time to find the velocity.