D = D. + V.T + (AT^2)/2
(AT^2)/2 = D - D. - V.T
AT^2 = 2 (D - D. -V.T)
A = [2 (D - D. - V.T)] / T^2
D is the Final Displacement
D. is Initial Displacement
V. is Initial Velocity
A is Acceleration
T is Time
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s = u + at s = displacement u = initial velocity a = acceleration t = time rearrange to give u = s - at and sub in values
vf2 = vi2 + 2ad, where vf is final velocity, vi is initial velocity, a is acceleration, and d is displacement. Solve for a.vf = vi + at, where t is time time. Solve for a.
Use the formula Acceleration = (final velosity - initial velocity)/ time.
You use the information you're given, along with the equations and formulas you know that relate distance, time, speed, and acceleration, to calculate the number you're asked to find. And here's a tip: Chances are that the initial acceleration, the final acceleration, and the acceleration all along the way, are all the same number.
v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration