You measure the gradient, which is rise/run or (change in vertical direction)/(change in horizontal direction). This is denoted by m. You also measure the height of the y-intercept: this is c.Then the equation is y = mx + c.
An equation of a line requires two parameters. The slope, by itself, is not enough.
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To determine which points are on the line given by the equation ( y = 2x ), you can substitute the x-coordinate of each point into the equation and see if the resulting y-coordinate matches the point's y-coordinate. For example, if you have the point (1, 2), substituting ( x = 1 ) gives ( y = 2(1) = 2 ), so this point is on the line. Repeat this process for each point to find which ones satisfy the equation.
To determine if a point is on a line, you can use the equation of the line. For example, if the line is represented by the equation (y = mx + b) (slope-intercept form), substitute the x-coordinate of the point into the equation to see if the resulting y-value matches the point's y-coordinate. If they match, the point lies on the line; if not, it does not. Alternatively, you can use other forms of the line equation, such as standard form, to perform a similar check.
To determine if a point is on a line, you can substitute the coordinates of the point into the equation of the line. If the equation holds true after substitution, the point lies on the line. For example, for a line defined by (y = mx + b), if you plug in the x-coordinate of the point and the resulting y-value matches the y-coordinate of the point, then it is on the line. Otherwise, the point is not on the line.
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
An equation of a line requires two parameters. The slope, by itself, is not enough.
i am cute
By finding the line of best fit and using the straight line equation formula.
To determine which points are on the line given by the equation ( y = 2x ), you can substitute the x-coordinate of each point into the equation and see if the resulting y-coordinate matches the point's y-coordinate. For example, if you have the point (1, 2), substituting ( x = 1 ) gives ( y = 2(1) = 2 ), so this point is on the line. Repeat this process for each point to find which ones satisfy the equation.
To determine if a point is on a line, you can use the equation of the line. For example, if the line is represented by the equation (y = mx + b) (slope-intercept form), substitute the x-coordinate of the point into the equation to see if the resulting y-value matches the point's y-coordinate. If they match, the point lies on the line; if not, it does not. Alternatively, you can use other forms of the line equation, such as standard form, to perform a similar check.
To determine if a point is on a line, you can substitute the coordinates of the point into the equation of the line. If the equation holds true after substitution, the point lies on the line. For example, for a line defined by (y = mx + b), if you plug in the x-coordinate of the point and the resulting y-value matches the y-coordinate of the point, then it is on the line. Otherwise, the point is not on the line.
Subtract the equation of one line from the equation of the other
As for example in the straight line equation of y=3x+5 the slope is 3 and the y intercept is 5
If the x intercept is a and the y intercept is b, then the equation of the line is bx + ay = ab
By substitution
The question is suppose to read: Find the equation of the line tangent to y=(x²+3x)²(2x-2)³, when x=8