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How do you find the equation of a tangent line?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
Show that x plus 2y equals 7 is a tangent to the circle x2 plus y2 -4x -1 equals 0?
x + 2y = 7 so x = 7 - 2ySubstitute in the equation of the circle:(7 - 2y)^2 + y^2 - 4*(7 - 2y) - 1 = 049 - 28y + 4y^2 + y^2 - 28 + 8y - 1 = 0=> 5y^2 - 20y + 20 = 0=> y^2 - 4y + 4 = 0 => y = 2and therefore x = 7 - 2y = 3Thus the straight line intersects the circle at only one point (3, 2) and therefore it must be a tangent.
Why does m. in abbreviation to slope mean?
Slope is the tangent of the angle between a given straight line and the x-axis of a system of Cartesian coordinates
What is the equation of the line containing the points (7, 3), (14, 6), and (21, 9)?
Points: (7, 3) (14, 6) (21, 9) Slope: 3/7 Equation: 7y=3x
1500 kva transformer equals how many amps at 480 volts?
480 volts is probably 3-phase (Line to line) voltage, so: 1500K / (480 x 1.732) = I = 1804Amps
How do you find the equation of a tangent line?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
Find the equation of the line tangent to the graph of y equals cos2x at x equals pi divided by 4?
0.5
What is the equation of the line tangent to the graph y equals sin 2x?
That line is [ y = 2 cos(2x) ].
Find the equation of a tangent line?
find the derivative to get the slope, then using the graph of the other line given to you, find a point on the graph that they share and plug it in to find the y-value. then use the point slope formulahttp://docs.google.com/gview?a=v&q=cache:P72siWJTFjwJ:gato-docs.its.txstate.edu/slac/Subject/Math/Calculus/Findting-the-Equation-of-a-Tangent-Line/Finding%2520the%2520Equation%2520of%2520a%2520Tangent%2520Line.pdf+how+to+find+the+equation+of+a+tangent+line&hl=en&gl=us&sig=AFQjCNFcYzt1d-PU9hE2gbQKngp4FeRw3Q
An equation of the line tangent to the graph of y equals x3 plus 3x2 plus 2 at its point of inflection is?
(a) y = -3x + 1
How do you find the equation of a tangent line to the graph of fx equals x cubed and x equals -2?
Calculate the derivative of the function.Use the derivative to calculate the slope at the specified point.Calculate the y-coordinate for the point.Use the formula for a line that has a specified slope and passes through a specified point.
Derivative as the Slope of a Tangent?
Yes, the derivative of an equation is the slope of a line tangent to the graph.
What is the equation of the line tangent to the curve y equals cos x at the point x equals pi over 6?
y = 2(x) - (pi/3) + (sqrt(3)/2)
Find the equation of the tangent line at the given value y equals ln x squared at x equals 1?
Given y=LN(x2). To find the equation of a tangent line to a point on a graph, we must figure out what the slope is at that exact point. We must take the derivitave with respect to x to come up with a function that will give the slope of the tangent line at any point on the graph. Any text book will tell you that the derivative with respect to X of LN(U) is the quantity U prime over U(In other words, the derivitive of U over U. U is whatever is inside the natural log). In this case, it is y = (2x/x2). To find the slope, we then plug in an x coordinate, 1. We get y=2. The slope of the tangent line at this point is 2. We now have m for the slope-intercept form y = mx + b. Now we must find b. B is the y intercept, aka where does the graph intersect the y axis. We use the slope. We know that the graph of the tangent line contains the point (0,1). We go down 2 and left one, to find that the tangent line intercepts the y axis at -1. We now have B. The equation of the tangent line of y = LN(x2) at X = 1 is y = 2X-1. Hope this helps!!!
How do you prove that the line y equals x-4 is tangent to the curve of x squared plus y squared equals 8?
equation 1: y = x-4 => y2 = x2-8x+16 when both sides are squared equation 2: x2+y2 = 8 Substitute equation 1 into equation 2: x2+x2-8x+16 = 8 => 2x2-8x+8 = 0 If the discriminant of the above quadratic equation is zero then this is proof that the line is tangent to the curve: The discriminant: b2-4ac = (-8)2-4*2*8 = 0 Therefore the discriminant is equal to zero thus proving that the line is tangent to the curve.
What is the definition of a tangent line?
A tangent is a line that just touches a curve at a single point and its gradient equals the rate of change of the curve at that point.
Find an equation of the line tangent to the curve defined by x^2+3xy+y^4=32 at the point (2,2)?
55
