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How do you find the equation of a tangent line?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
Show that x plus 2y equals 7 is a tangent to the circle x2 plus y2 -4x -1 equals 0?
x + 2y = 7 so x = 7 - 2ySubstitute in the equation of the circle:(7 - 2y)^2 + y^2 - 4*(7 - 2y) - 1 = 049 - 28y + 4y^2 + y^2 - 28 + 8y - 1 = 0=> 5y^2 - 20y + 20 = 0=> y^2 - 4y + 4 = 0 => y = 2and therefore x = 7 - 2y = 3Thus the straight line intersects the circle at only one point (3, 2) and therefore it must be a tangent.
Why does m. in abbreviation to slope mean?
Slope is the tangent of the angle between a given straight line and the x-axis of a system of Cartesian coordinates
What is the equation of the line containing the points (7, 3), (14, 6), and (21, 9)?
Points: (7, 3) (14, 6) (21, 9) Slope: 3/7 Equation: 7y=3x
1500 kva transformer equals how many amps at 480 volts?
480 volts is probably 3-phase (Line to line) voltage, so: 1500K / (480 x 1.732) = I = 1804Amps
