Q: How do you find base of triangle with area 35 meters and altitude 14 meters?

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Area of a triangle = (0.5) * (Base) * (Altitude) = (0.5) * (6 meters) * (8 meters) = 24 square meters

Area of a triangle = (1/2) (base) (height)= (1/2) (12) (14) = 84 square meters

The area of triangle is : 64.0

Area of a triangle = 1/2*base*altitude in square units Area = 45 square feet

Area = 0.5*base*altitude

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Area of a triangle = (0.5) * (Base) * (Altitude) = (0.5) * (6 meters) * (8 meters) = 24 square meters

Since the area is equal to 1/2 of the product of base and altitude, the base of this triangle must be 4 meters.

Area of a triangle = (1/2) (base) (height)= (1/2) (12) (14) = 84 square meters

The area of triangle is : 64.0

A base is normally a line and therefore has no area; the area of a triangle is half of base x altitude.

Area = 0.5*base*altitude

altitude(height)=(Area * 2) /length(Base)

Area of a triangle = 1/2*base*altitude in square units Area = 45 square feet

Let the given area is 10cm. Base of the triangle is 4 cm. altitude of triangle=? Area= 1/2 x Base x altitude 10= 1/2 x 4x altitude 10=2 x altitude 10/2= altitude 5= altitude Hence, altitude of the triangle is 5 cm.

Area = 0.5*base*altitude

The area of triangle is : 90.0

The area of triangle is : 100.0