By solving the simultaneous equations the values of x and y should be equal to the given coordinate
If you have two equations give AND one parametric equation why do you need to find yet another equation?
Bggvgvvguo
It depends on what equations are given.
To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).
To find the solution of two equations graphed on a coordinate plane, look for the point where the two lines intersect. This point represents the values of the variables that satisfy both equations simultaneously. The coordinates of this intersection point are the solution to the system of equations. If the lines are parallel, there is no solution; if they are the same line, there are infinitely many solutions.
If you have two equations give AND one parametric equation why do you need to find yet another equation?
Bggvgvvguo
It depends on what equations are given.
There are very many equations which depend on what information you have been given.
If the equations are in y= form, set the two equations equal to each other. Then solve for x. The x value that you get is the x coordinate of the intersection point. To find the y coordinate of the intersection point, plug the x you just got into either equation and simplify so that y= some number. There are other methods of solving a system of equations: matrices, substitution, elimination, and graphing, but the above method is my favorite!
To find the vertex of a quadratic equation in standard form, (y = ax^2 + bx + c), you can use the vertex formula. The x-coordinate of the vertex is given by (x = -\frac{b}{2a}). Once you have the x-coordinate, substitute it back into the equation to find the corresponding y-coordinate. The vertex is then the point ((-\frac{b}{2a}, f(-\frac{b}{2a}))).
I suggest that the simplest way is as follows:Assume the equation is of the form y = ax2 + bx + c.Substitute the coordinates of the three points to obtain three equations in a, b and c.Solve these three equations to find the values of a, b and c.
MATLAB can be used to find the roots of a given equation by using the built-in functions like "roots" or "fzero". These functions can solve equations numerically and provide the values of the roots. By inputting the equation into MATLAB and using these functions, the roots can be easily calculated and displayed.
To find the solution of two equations graphed on a coordinate plane, look for the point where the two lines intersect. This point represents the values of the variables that satisfy both equations simultaneously. The coordinates of this intersection point are the solution to the system of equations. If the lines are parallel, there is no solution; if they are the same line, there are infinitely many solutions.
You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.
To find the x-coordinate of the solution to a system of equations, you would typically solve the equations simultaneously. However, since no specific equations were provided, I cannot calculate or provide a numerical answer. Please provide the equations for further assistance.
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7