Easily put any number with a single odd number 1,3,5,7,9 in a three digit number. Like 113 the 3 and 1 makes it odd number or 223 the three makes it odd.
There are 17 such numbers.
The highest four-digit number using three odd digits is 9997. This is achieved by using the digit '9' three times (the highest odd digit) and the next highest odd digit, which is '7', to complete the four-digit requirement. Therefore, the combination of three '9's and one '7' results in the number 9997.
1, 3, and 5.
874
3897
There are 17 such numbers.
111 and 201
450... There are 500 odd numbers from 000 to 999 inclusive. From 000 to 099, there are 50 odd numbers. 500 - 50 = 450.
1, 3, and 5.
874
450.
3897
Since both of those numbers contains four digits, there are no three-digit numbers between them.
The last digit in the product of the first 20 odd natural numbers can be determined by looking at the pattern of the units digit in the multiplication of consecutive odd numbers. The units digit of the product of consecutive odd numbers alternates between 1 and 5. Since there are 10 odd numbers between 1 and 19, and 20 is also an odd number, the last digit in the product of the first 20 odd natural numbers is 5.
There are 899 three digit numbers (100 through 999).Each century (grouping of 100 numbers) has 50 odd numbers. (half of the numbers are odd, half are even)So.. 100-199, 200-299, 300-399, 400-499, 500-599, 600-699, 700-799, 800-899, 900-999We have 9 centuries.Number of odd numbers = 9*50 = 450
Meaningless question.
To find the number of five-digit odd numbers where the leftmost digit cannot be zero, we consider the structure of a five-digit number: ABCDE. The leftmost digit (A) can be any digit from 1 to 9 (9 choices). The last digit (E) must be odd, which gives us 5 choices (1, 3, 5, 7, or 9). The middle three digits (B, C, D) can each be any digit from 0 to 9 (10 choices each). Thus, the total number of such five-digit odd numbers is (9 \times 10 \times 10 \times 10 \times 5 = 45000).