Q: How do you find out a perimerter?

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The perimeter also doubles.

45 ft wide

Each side is 9 inches long

A hexagon has 6 sides, so, if one edge = 5m, 6x5 = 30 so your answer is 30 m

L + W = P/2 = 34, so L = 34 - W;L x W = 280 or (34 - W) x W = 280 ie 34W - W2 = 280 which is W2 - 34W + 280 = 0This factorises as (W - 14)(W - 20) so the sides are 14 and 20 feet, the latter being the longer.

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It is 4 times the side length.

26 meters

Circumference is the word you are looking for.

The perimeter also doubles.

6*3.25 = 19.5 m

45 ft wide

Each side is 9 inches long

A square with a side length of 10 metres (40/4) has an area of 100 square metres.

A hexagon has 6 sides, so, if one edge = 5m, 6x5 = 30 so your answer is 30 m

An SSA triangle is ambiguous.Suppose the triangle is ABC and, with conventional labelling, you know a, b and angle A.Then by the cosine rule, a2 = b2 + c2 - 2bc*Cos(A)This equation will give rise to a quadratic equation in cwhich has 2 solutions. The perimeter is then a + b + c1 or a + b + c2

The perimetre is 60cm.Because a perfect square has equal sides, which are in length the square root of the area because multiplying the length of a square by itself gives it's area. So:sqrt(225) = 15cmA square has 4 sides of the same length, so if 1 side is 15cm all 4 sides that form the perimetre must be 15*4=60cm.

L + W = P/2 = 34, so L = 34 - W;L x W = 280 or (34 - W) x W = 280 ie 34W - W2 = 280 which is W2 - 34W + 280 = 0This factorises as (W - 14)(W - 20) so the sides are 14 and 20 feet, the latter being the longer.