you do length times width like 4 time 6 = ...
add da numbers enig
With great difficulty since such a shape cannot exist. A cuboid, by definition, has six faces (sides).
length *width*height=area of cuboid
The surface area of a cuboid can be calculated using the formula (2(ab + ac + bc)), where (a), (b), and (c) are the dimensions of the cuboid. For a cuboid with dimensions 1, 2, and 3, the surface area is (2(1 \cdot 2 + 1 \cdot 3 + 2 \cdot 3) = 2(2 + 3 + 6) = 2 \times 11 = 22) square units. Therefore, the surface area of the 1x2x3 cuboid is 22 square units.
Make it infinitesimally small.
derivation of surface area of cuboid
The surface area of a box, which is a cuboid, depends on its length, width and height. A cube is a special type of cuboid in which the length , width and height are all the same.
Lateral surface area of a cuboid = 2 (Length + Breadth) × Height Lateral surface area of a cube = 4 × Side2
A cuboid is a 3 dimensional object and 3 measures are required for the total surface area of a cuboid.
add da numbers enig
length *width*height=area of cuboid
With great difficulty since such a shape cannot exist. A cuboid, by definition, has six faces (sides).
A cuboid is a hexahedron. That is a solid face with six faces. More specifically, all six faces of a cuboid are rectangular. The total surface area of a cuboid with sides of length A, B and C is 2*(AB + BC + CA) sq units.
Let its dimensions be a, b and c:- Surface area of the cuboid: 2*(a*b)+2*(b*c)+2*(a*c) in square units
yes
Make it infinitesimally small.
The answer depends on what information is provided: the volume, total surface area, principal diagonal, minor diagonal, etc.